Consider the situation shown in the figure. Here 
is the maximum angle for which the light suffers total internal reflection at the vertical surface. Then sin 
will be:-
Text Solution
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00.75
The critical angle for this case is
or, 
Since 
, we have 
. From Snell's law,
or, 
or, 
If 
" is greater than the critical angle, 
will be smaller than this value. Thus, the maximum value of 
, for which total reflection takes place at the vertical surface, is sin -1 (3/4).
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